inverting amplifier

The circuit consists of a resistor in series with the voltage source connected to the inverting input of the OpAmp. The non-inverting input of the OpAmp is short circuited to ground(common). A resistor is connected to the output and provides a negative feedback path to the inverting input terminal.

inverting opamp and Since is connected to the common or ground terminal, Node 1 is said to be a virtual ground due to the virtual short circuit between the inverting and non-inverting terminals (which is grounded) as defined by the voltage constraints, The node voltage method of analysis is applied at node 1, By appling Equation , obtained from the virtual short circuit, and the constraint on the current as defined in Equation, Equation is simplified to Solving for the voltage gain, , Notice that the voltage gain is dependent only on the ratio of the resistors external to the OpAmp, and . The amplifier increases the amplitude of the input signal by this ratio. The negative sign in the voltage gain indicates an inversion in the signal.

The output voltage is also constrained by the supply voltages and , Using Equation , the maximum resistor ratio for a given input voltage is

实验

根据下图,计算增益和。如果,输出是多少?多大的输入电压幅值,会造成amplifier饱和?

inverting opamp example

Solution:

The output voltage is independent of the load resistor, , because of the low output resistance of the OpAmp. Therefore, the gain of amplifier is Using KCL at node a, The currents and are and Solving for yields, For and input voltage signal of 由于我使用的是模块,具体参考双电源供电

要计算amplifier的linear region,输入幅值需要小于,

一些实验结果

总体效果

big picture

输入

黄色为输入,左下角一个格子为1v,而蓝色一个格子为5v。

liner op region

输入为2v左右导致输出饱和

发现输出的顶部已经不再是正弦波。和理论计算比较一致。

saturation